mensuration Model Questions & Answers, Practice Test for ibps clerk prelims 2024
ibps clerk prelims 2024 SYLLABUS WISE SUBJECTS MCQs
Ratio & Proportion
Percentage
Time & Work
Time & Distance
Mensuration
Trigonometric Ratios & Identities
What is the height of a solid cylinder of radius 5 cm and total surface area is 660 sq cm?
Answer: (d)
Radius (r) = 5 cm
Total surface area = 660 $cm^2$
⇒ 2πrh + 2π$r^2$ = 660
⇒ 2πr (h + r) = 660
⇒ (h + 5) = ${330}/{5π} = {330}/5 × ∼ 7/{22}$
⇒ h = ${66 × 7}/{22}$ - 5 = 21 - 5 = 16cm.
A village having a population of 4000 requires 150 litres of water per head per day. It has a tank measuring 20 m × 15 m × 6 m. The water of this tank will last for
Answer: (c)
Volume of tank = 20 × 15 × 6 $m^3$
= 20 × 15 × 6 × 1000 litre
∴ The water of the tank will last for
${20 × 15 × 6 × 1000}/{150 × 4000}$ days.
i.e. The water of the tank will last for 3 days.
In the given figure, L is any point on the bisector of the acute angle ABC and the line ML is parallel to BC. Which one of the following is correct?
![mensuration area and volume aptitude mcq 22 53](https://careericons.com/adminicon/bunch/images/mensuration-area-and-volume-aptitude-mcq-22-53.png)
Answer: (a)
Since, BL is bisector of ∠ABC.
∠MBL = ∠LBC = x (say)
Also, ML ||BC
∠LBC = ∠MLB = x ⇒ ∠MLB = ∠MBL
ΔBLM is an isosceles triangle and ∠BML need not to be 90°.
ΔBML is isosceles but not right angled.
A semi-circular plate is rolled up to form a conical surface. The angle between the generator and the axis of the cone is
Answer: (a)
Since, the radius of semicircle = slant height of the cone = r
And the circumference of semicircle = circumference of base of cone.
πr = 2πR ⇒ $r/2$ = R.
In ΔOAB
sin θ = $R/r = {r/2}/r = 1/2$ = sin 30°
θ = 30°
The radius of the wheel of a bus is 70 cms and the speed of the bus is 66 km/h, then the r.p.m. (revolutions per minutes) of the wheel is
Answer: (c)
Radius of the wheel of bus = 70 cm. Then,
circumference of wheel = 2 πr = 140 π = 440 cm
Distance covered by bus in 1 minute
= ${66}/{60}$ × 1000 × 100 cms
Distance covered by one revolution of wheel
= circumference of wheel
= 440 cm
∴ Revolutions per minute = ${6600000}/{60 × 440}$ = 250
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